#### Mathematic Equation

Cylinder Force
lbs.(Pounds of Force)

Force=Pressure (psi) x Net Area (in²)

F=PA

Fluid Motor Speed
RPM (Revolutions per Minute)
Speed =  231 x Flow Rate (GPM)
F.M. Displacement (in³/rev.)
n = 231 Q
d
Fluid Pressure
psi (Pounds per Square Inch)
Pressure =  Force (lbs)
Area (in ²)

P= F
A

Fluid Motor Torque
lb-in (Inch Pounds)
Torque = Pressure (psi) x F.M. Displacement (in³/rev.)
TPd
TorqueHorsepower  x 63025
RPM
T = 63025 hp
n
Torque = Flow Rate (GPM) x Pressure (psi) x 36.77
RPM
T=36.77 Q P
N
Fluid Motor Power
hp (Horsepower)
Horsepower = Torque (lbs-in) x RPM
63025
hp=  Tn
63025
Cylinder Area Extend
in² (Square Inches)
Area = π/(4 x Bore Diameter ²) A = .7854 D²
Cylinder Area Retract (w/rod)
in² (Square Inches)
Area =  (π/4  x Bore Diameter²) –
(π/4 x Rod Diameter²)
A= (.7854 Db²)– (.7854 Dr²)
Cylinder Volume
G (Gallons of Fluid)
Volume = Net Area (in²) x Stroke (in)
231
V A L
231
Cylinder Power
hp (Horsepower)

Horsepower = Pressure (psi) x Flow Rate (GPM)
1714

hp = P Q
1714
Cylinder Velocity
ft/s (Feet per Second)

Velocity231 x Flow Rate (GPM)
12 x 60 x Net Area (in²)

v= .3208 Q
A

Pump Outlet Flow
GPM (Gallons per Minute)

Flow = RPM x Pump Displacement (in³/rev.)                                   231 Qnd
231
Flow Rate Through Piping
ft/s Velocity (Feet per Second)

Velocity= .3208 x Flow Rate Through I.D. (GPM)
Internal Area (in²)

v=.3208Q
A